Two identical containers have the same volume of water in it. Each of them is placed on a balance and readings of the two balances are same. There is a hollow ball and a solid ball that have same volume. The hollow ball floats in water and the solid ball sinks. A string from the ceiling suspends the solid ball so that it remains completely submerged in the water in the first container. The hollow ball is held submerged in the water in the second container and is held by a string fastened to the bottom of the container. Which balance will show higher reading? How will your answer change if the string in the second container is cut?

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Second balance

First balance

Both balance will show the same reading

Insufficient information to compare the readings of the two balances.

answer is A.

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Detailed Solution

Buoyancy on both balls, when completely submerged will be same (say F_B).
This F_B is large than weight of the hollow ball.
In first container, the ball exerts a force F_B on the water + container system.
This increases the reading of the balance by F_B
In second container, the reading increases by an amount equal to weight of the hollow ball (that is less then $F_{B}$ ).

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