Two identical containers joined by a small pipe initially contain the same gas at pressure P0 and absolute temperature T0. One container is now maintained at the same temperature while the other is heated to 2T0. The common pressure of the gases will be

n1+n2i=n1+n2for p0VRT0+p0VRT0=pVRT0+pV2RT0or 2p0VRT0=3pV2RT0∴ p=43p0

Two identical containers joined by a small pipe initially contain the same gas at pressure P0 and absolute temperature T0. One container is now maintained at the same temperature while the other is heated to 2T0. The common pressure of the gases will be

n1+n2i=n1+n2for p0VRT0+p0VRT0=pVRT0+pV2RT0or 2p0VRT0=3pV2RT0∴ p=43p0

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Two identical containers joined by a small pipe initially contain the same gas at pressure $P_{0}$ and absolute temperature T₀. One container is now maintained at the same temperature while the other is heated to 2T₀. The common pressure of the gases will be

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$\frac{3}{2} ρ_{0}$

$\frac{4}{3} ρ_{0}$

2 $ρ_{0}$

$\frac{5}{3} ρ_{0}$

answer is B.

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Detailed Solution

${(n_{1} + n_{2})}_{i} = {(n_{1} + n_{2})}_{f}$

or $\frac{p_{0} V}{R T_{0}} + \frac{p_{0} V}{R T_{0}} = \frac{p V}{R T_{0}} + \frac{p V}{2 R T_{0}}$

or $\frac{2 p_{0} V}{R T_{0}} = \frac{3 p V}{2 R T_{0}}$

$∴ p = \frac{4}{3} p_{0}$

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Two identical containers joined by a small pipe initially contain the same gas at pressure P0 and absolute temperature T0. One container is now maintained at the same temperature while the other is heated to 2T0. The common pressure of the gases will be

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Two identical containers joined by a small pipe initially contain the same gas at pressure $P_{0}$ and absolute temperature T₀. One container is now maintained at the same temperature while the other is heated to 2T₀. The common pressure of the gases will be