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Two identical heaters rated 220 V, 1000 W are placed in series with each other across 220 volt line; then the equivalent combined power in the circuit is

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1000 W

2000 W

500 W

4000 W

answer is C.

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Detailed Solution

For each heater resistance is given by $R = \frac{V^{2}}{P} = \frac{(220)^{2}}{1000} Ω$

For series connection, $R_{eq} = R + R = 2 R$

Combined power, $P_{eq} = \frac{V^{2}}{R_{eq}} = \frac{(220)^{2}}{2 \frac{(220)^{2}}{1000}} = 500 W$

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