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Two identical metal bob having charge Q on each, are suspended by two insulated string of equal length L metre, from a hook fixed to a stand. The whole set up is taken in satellite into space where there is no gravity (state of weightlessness). Then the angle between the string and tension in the string is

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$90^{o}, \frac{1}{4 {πε}_{o}} . \frac{Q^{2}}{L^{2}}$

$180^{o}, \frac{1}{4 {πε}_{o}} . \frac{Q^{2}}{2 L^{2}}$

$180^{o}, \frac{1}{4 {πε}_{o}} . \frac{QL}{4 L^{2}}$

$180^{o}, \frac{1}{4 {πε}_{o}} . \frac{Q^{2}}{{(2 L)}^{2}}$

answer is A.

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Detailed Solution

In case of weightlessness, following situation arises

So angle $θ$ = 180° and force F = $\frac{1}{4 {πε}_{0}} . \frac{Q^{2}}{{(2 L)}^{2}}$

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