Two identical moving coil galvanometers have $10\Omega$ resistance and full scale deflection at $2\mu A$ current. One of them is converted into a voltmeter of 100mV full scale reading and the order into an Ammeter of 1mA full scale current using appropriate resistors. These are then used to measure the voltage and current in the Ohm’s law experiment with R=1000$\Omega$  resistor by using an ideal cell. Which of the following statement(s) is/are correct?

Option 4:    $\left(I_g\right)G=\left(I\right)\left(R_A\right)$    

$\Rightarrow \left(2\times {10}^{-6}\right)10=\left(1\times {10}^{-3}\right)R_A$
 $\therefore$ Resistance of ammeter $R_A=0.02\Omega$  (4)  is correct
Option 3: $V=\left(I_g\right)R_V$  $\therefore R_V=\frac{V}{I_g}=\frac{{10}^{-1}}{2\times {10}^{-6}}=5\times {10}^4\Omega$   $=50k\Omega$ $\therefore$(3) is wrong
Option 2:

 
$R_1=\frac{R.R_V}{R+R_V},R_2=R_A$  Reading of ammeter = I
Reading of voltmeter V = IR
Measured value of resistance is $R_m=\frac{V}{I}=R_1$ 
$=\frac{R.R_V}{R+R_V}=\frac{{10}^3\times 5\times {10}^4}{{10}^3+5\times {10}^4}=\frac{5\times {10}^4}{51}=980.4\Omega \therefore \left(2\right)$ is correct
Option 1: measured value of R depends on R and $R_V$ only, but independent of $R_A$ and r values.  Measured value of resistance will again be $980.4\Omega$ only