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Two identical parallel plate capacitors are joined in series to 100 V battery. Now a dielectric with K = 4 is introduced between the plates of second capacitor. The potential difference on capacitors are

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75 V, 25 V

80 V, 20 V

70 V, 30 V

60 V, 40 V

answer is D.

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Detailed Solution

C and 4C are in series
C₁ & C₂ are in series $C_{s} = \frac{4 C}{5}; Q = \frac{4 C}{5} \times 100$
$V_{1} = \frac{Q}{C} = 80 V; V_{2} = 20 V$

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