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Two identical particles each having a charge of 10 µC are tied with two strings of equal length 1 m at a common point. If both the strings makes an angle of 30° with vertical, then mass of each particle will be :

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0.5 kg

0.1 kg

0.15 kg

1 kg

answer is C.

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Detailed Solution

$T \cos 30^{o} = mg and T \sin 30^{o} = \frac{{kq}^{2}}{l^{2}} \Rightarrow \tan 30^{o} = \frac{{kq}^{2}}{l^{2} mg} \Rightarrow m = \frac{{kq}^{2} \sqrt{3}}{l^{2} g} = 0.15 kg$

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