Two identical pith balls are charged by rubbing against each other. They are suspended from a horizontal rod through two strings of length 20 cm each, the separation between suspension points being 5 cm. In equilibrium the separation between the balls is 3 cm. If the charge on each ball has a magnitude of 2 × 10^-8 C then the tension in the string is P × 10^-2 ( P is an integer). The value of ' P ' is..

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answer is 8.

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Force between charges $F = \frac{k q^{2}}{r^{2}} = 4 \times 10^{- 3} N$
Also $T \sin θ = F$
$Tension T = \frac{F}{\sin θ} = \frac{4 \times 10^{- 3}}{(\frac{1}{20})} = 8 \times 10^{- 2} N$

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