Two identical plates $P_{1}$ and $P_{2},$ of cross sectional area A are separated at a very small distance d, where $\frac{ε_{0} A}{d} = 2 F .$ Initially charge on the plate $P_{1}$ is -10 C and charge on the plate $P_{2}$ is +30 C. Now plate $P_{1}$ and $P_{2}$ are connected to positive and negative terminals of battery of potential difference 10 Volts with the help of switches $S_{1}$ and $S_{2}$ respectively. Choose the correct option (s) when $S_{1} & S_{2}$ are closed

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The net charge on the plate $P_{2}$ is -10 C

The work done by the battery is 200 J.

The charge on the right side of the plate $P_{2}$ is 20C.

The charge on the left side of the plate $P_{1}$ is 10C.

answer is B, C.

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Detailed Solution

Question Image $\frac{q}{A ε_{0} \times d} = 10 \Rightarrow 10 \times \frac{A ε_{0}}{d} = 20 C$
$Q = 20 + 10 = 40 C$
$W_{B} = (20 + 20) 10 = 400 J$

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