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Two identical projectiles are fired simultaneously as shown from the ground with the same magnitude for the velocity and at the same angle with respect to the horizontal. The two projectiles collide at the highest point 'B' and coalesce. After how much time of firing them, they reach the ground ?

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$\frac{u sin α}{g}$

$\frac{u \cos α}{g}$

$\frac{2 u sin α}{g}$

$\frac{2 u \cos α}{g}$

answer is C.

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Detailed Solution

$Time taken to reach highest point = \frac{usinα}{g}$

$At highest point, m (usinα) - m (usinα) = 0$

They fall freely to ground

$Time of fall t_{d} = \sqrt{\frac{2 H}{g}} = \sqrt{\frac{2}{g}} (\frac{u^{2} \sin^{2} α}{2 g}) = \frac{usinα}{g}$

$Total time from firing is t = \frac{2 usinα}{g}$

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