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Two identical rods each of cross-sectional area $A$ are placed on smooth horizontal surface. These are acted by forces as shown in figure. The breaking strength of material of each rod is $F / A$ , then :

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rod $A B$ will break left of the centre

rod $A B$ will break right of the centre

rod $C D$ will break left of the centre

rod $C D$ will break right of the centre

answer is B, C, D.

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Detailed Solution

$(2, 3, 4)$ The pseudoforce force at the middle of rod $A B$ will be $F$ . So stress to the right of middle will be greater than $F / A$ . The force at each section of rod $C D$ is $F$ . So stress at each section is $F / A$ .

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