Two identical satellites are orbiting at a distance R & 7R from the surface of the earth, R being the radius of the earth. The ratio of their

$\text{K}{\text{.E}}_1=\frac{\text{GMm}}{2\left(\text{R}+\text{R}\right)},\text{K}{\text{.E}}_2=\frac{\text{GMm}}{2\left(\text{R}+7\text{R}\right)}$                        

$\frac{{\text{K}}_1}{{\text{K}}_2}=\frac{16}{4}=4$

${\text{K}}_1:{\text{K}}_2=4:1$

(ii) $\text{P}{\text{.E}}_1=\frac{-\text{GMm}}{\text{R}+\text{R}},\text{P}{\text{.E}}_2=\frac{-\text{GMm}}{\text{R}+7\text{R}}$                            

$\frac{{\text{P}}_1}{{\text{P}}_2}=\frac{8}{2}\frac{\text{R}}{\text{R}}=\frac{4}{1}$

${\text{P}}_1:{\text{P}}_2=4:1$

(iii) $\text{T}\text{.E}=\frac{-\text{GMm}}{2\left(\text{R}+\text{h}\right)}$

$\text{T}{\text{.E}}_1=\frac{-\text{GMm}}{4\text{R}}$

$\text{T}{\text{.E}}_2=\frac{-\text{GMm}}{2\left(\text{R}+\text{7R}\right)}=\frac{-\text{GMm}}{16\text{R}}$

$\frac{\text{T}{\text{.E}}_1}{\text{T}{\text{.E}}_2}=\frac{4}{1}$