Two identical solid copper spheres of radius R placed in contact with each other. The gravitational attracton between them is proportional to

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R^-2

R²

R⁴

R^-4

answer is C.

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Detailed Solution

$\begin{array}{l} F = \frac{G \times m \times m}{(2 R)^{2}} = \frac{G \times {(\frac{4}{3} {πR}^{3} ρ)}^{2}}{4 R^{2}} = \frac{4}{9} π^{2} ρ^{2} R^{4} \\ ∴ F \propto R^{4} \end{array}$

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