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Two identical springs of constant k are connected in series and parallel as shown in figure. A mass M is suspended from them. The ratio of their frequencies of vertical oscillations will be:

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2 : 1

1 : 2

1 : 4

4 : 1

answer is B.

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Detailed Solution

$\begin{aligned} k_{eq} = \frac{k_{1} k_{2}}{k_{2} + k_{2}} (series) \\ k_{eq} = k_{1} + k_{2} (parallel) \end{aligned}$

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