Two identical strings X and Z made of same material have tension T_X and T_Z in them. If their fundamental frequencies are 450 Hz and 300 Hz, respectively, then the ratio $\frac{T_{X}}{T_{Z}}$ is:

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0.44

1.25

1.5

2.25

answer is C.

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Detailed Solution

$f = \frac{1}{2 ℓ} \sqrt{\frac{T}{μ}}$
For identical string $l$ and $μ$ will be same
$\begin{array}{l} f \propto \sqrt{T} \\ \frac{450}{300} = \sqrt{\frac{T_{x}}{T_{y}}} \\ \frac{T_{x}}{T_{y}} = \frac{9}{4} = 2 .25 \end{array}$

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