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Two identical vessels each of volume V contain identical samples of ideal gas. The pressure and temperature in each are P and 2T respectively. Now they are joined by a very narrow pipe and one of them is cooled to a temperature T and the other one is heated to a temperature 3T. The common pressure of the system now is

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4P/3

3P/2

3P/4

3P/5

answer is C.

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Detailed Solution

The total number of moles is same. Apply PV = nTR. $2 (\frac{PV}{2 TR}) = (\frac{P'V}{TR}) + (\frac{P'V}{3TR})$ . Solve for the common pressure $P'$

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