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Q.

Two immiscible liquids P and Q of different densities are  contained in a wide U-tube as shown in Fig. 12.54. The heights of the two liquids above the horizontal line XX' which cuts the boundary between the liquids are Hp and HQ respectively. The U-tube is transported to a planet where the acceleration of free fall is 23 that on the earth, where the 3 liquids do not evaporate and where the heights of liquid  (measured relative to XX' ) are hp and hQ respectively. 
Which of the given statements is correct?
 

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a

Both liquid levels rise up so that hp - hQ = Hp -HQ

b

The liquid P falls and liquid Q rises such that hphQ=2Hp3HQ

c

Both liquid levels rise up so that hp /Hp = hQ /HQ

d

The liquid levels are unchanged, i.e., hp = Hp and hQ = HQ

answer is A.

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Detailed Solution

ρ1gh1=ρ2gh2  so liquid column heights are independent of acceleration due to gravity.

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Two immiscible liquids P and Q of different densities are  contained in a wide U-tube as shown in Fig. 12.54. The heights of the two liquids above the horizontal line XX' which cuts the boundary between the liquids are Hp and HQ respectively. The U-tube is transported to a planet where the acceleration of free fall is 23 that on the earth, where the 3 liquids do not evaporate and where the heights of liquid  (measured relative to XX' ) are hp and hQ respectively. Which of the given statements is correct?