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Q.

Two inductors A and B when connected in parallel are equivalent to a single inductor of inductance 1.5 H, and when connected in series are equivalent to a single inductor of inductance 8 H. Find the difference in the inductances of A and B.

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a

7.5 H

b

4 H 

c

3 H 

d

2 H 

answer is D.

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Detailed Solution

L1L2L1+L2=1.5 L1+L2=8 (L1−L2)2=(L1+L2)2−4L1L2 ∴L1−L2=4H

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