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Two infinite planes each with uniform surface charge density + $σ$ are kept in such a way that the angle between them is 30°. The y component of electric field in the region shown between them is given by $\frac{p σ}{2 \in_{0}} \times 10^{- 3}$ SI units. The value of p is (Rounded off to the nearest integer)

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answer is 134.

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Detailed Solution

$\vec{E} = \frac{σ}{2 ε_{0}} \cos 60 ° (- \hat{x}) + [\frac{σ}{2 ε_{0}} - \frac{σ}{2 ε_{0}} \sin 60 °] (\hat{y})$

$\vec{E} = \frac{σ}{2 ε_{0}} [(1 - \frac{\sqrt{3}}{2}) \hat{y} - \frac{1}{2} \hat{x}]$

$\Rightarrow p \times 10^{- 3} = 1 - \frac{\sqrt{3}}{2} \approx 0.134$

$p = 134$

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