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Q.

Two kg of water is converted into steam by boiling at atmospheric pressure. The volume changes from $2 \times 10^{- 3} m^{3} t o 3.34 m^{3}$ . The work done by the system is about:

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a

-340 kJ

b

340 kJ

c

-170 kJ

d

170 kJ

answer is D.

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Detailed Solution

$W = P ∆ V = 1.01 \times 10^{5} (3.34 - 2 \times 10^{- 3}) = 337 \times 10^{3} J \approx 340 K J$

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