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Two lighter nuclei combine to form a comparatively heavier nucleus by the relation given below : $_{1}^{2} X +_{1}^{2} X =_{2}^{4} Y$
The binding energies per nucleon $_{1}^{2} X {and}_{2}^{4} Y$ are 1.1 MeV and 7.6 MeV respectively. The energy released in this process is_______ . MeV.

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answer is 26.

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Detailed Solution

Energy released in the given process = Binding energy of product – Binding energy of reactants

$\begin{array}{l} = 7 .6 \times 4 - (1 .1 \times 2) \times 2 \\ = 30 .4 - 4 .4 \\ = 26 MeV \end{array}$

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