Two lines are given to be parallel. The equation of one line is 4𝑥 + 3𝑦 = 14, then find the equation of the other line.

We are given that two lines are parallel, and one of the lines is 4𝑥 + 3𝑦 = 14. For a pair of parallel lines, if two equations are 𝑎₁ 𝑥 + 𝑏₁ 𝑦 + 𝑐₁ = 0 and 𝑎₂ 𝑥 + 𝑏₂ 𝑦 + 𝑐₂ = 0

then, 

$\frac{a1}{a2}=\frac{b1}{b2}$

Here, a1 = 4 , b1 = 3 and c1 = -14

So, putting these values in the above condition, we get

$\frac{4}{a_2} = \frac{3}{b_2}$

$\frac{a_2}{b_2} = \frac{4}{3}$

So, the ratio of the first two coefficients should equal the ratio of coefficients of the given equation.

Hence, the second equation is 8𝑥 + 6𝑦 − 30 = 0.