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Q.

Two liquids A and B have PA and PB in the ratio of 1 : 3 and the ratio of number of moles of A and B in liquid phase are 1 : 3 then mole fraction of ‘A’ in vapour phase in equilibrium with the solution is equal to

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a

0.1

b

0.2

c

0.5

d

1.0

answer is A.

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Detailed Solution

xA=14,xB=34yA=pAxApT(1)yB=pBxBpT(2)yAyB=pApBxAxByA1yA=13×139yA=1yAyA=0.1

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