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Two liquids are at 40°C and 30°C. When they are mixed to equal masses, the temperature of the mixture is 36°C. Ratio of their specific heats is

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2 : 3

4 : 3

3 : 2

3 : 4

answer is A.

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Detailed Solution

$m_{1} s_{1} (T - T_{1}) = m_{2} s_{2} (T_{2} - T) \Rightarrow \frac{s_{1}}{s_{2}} = \frac{T_{2} - T}{T - T_{1}} = \frac{36 - 30}{40 - 36} = \frac{3}{2}$

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