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Two long metallic strips are joined together by two rivets each of radius 2 mm. Each rivet can withstand a maximum shearing stress of $1.5 \times 10^{9} N / m^{2}$ . Assuming that each rivet shares the stretching load equally, the maximum tensile force the strip can exert without rupture is

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$1.88 \times 10^{4} N$

$3.8 \times 10^{4} N$

$6 \times 10^{7} N$

$3 \times 10^{4} N$

answer is B.

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Detailed Solution

Let the maximum tensile force that each rivet can experience be F, then maximum shearing stress on each rivet is

$\begin{array}{l} σ = \frac{F}{A} = 1 .5 \times 10^{9} \\ A = {πr}^{2}, where r = 2 \times 10^{- 3} m \end{array}$

Required force is 2F.

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