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Q.

Two long parallel conductors carry 100 A current. If the conductors are separated by 20 mm, the force per metre of length of each conductor will be

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a

0.1 N

b

10 N

c

100 N

d

1 N

answer is D.

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Detailed Solution

$\frac{F}{L} = \frac{μ_{0} I_{1} I_{2}}{2 π d}$

the force acting per unit length of the conductor

here I₁=I₂=100 A, d=20 x 10^-3 m; $\frac{μ_{0}}{2 π}$ =2x10^-7

we get, F/L=0.1 N/m

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