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Q.

Two long, parallel straight wires carry equal currents in opposite directions . The separation between the wires is 5.0 cm. If a particle of charge 5 μC moves with a velocity 500 ms-1 into the plane of the conductors , at a point P midway between the wires , then the force on the particle will be

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a

4 x 10-5 N

b

4 x 10-7 N

c

zero

d

4 x 10-6 N

answer is C.

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Detailed Solution

F→=q(V→×B→)V→ is parallel to B→⇒F=0

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