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Two long, parallel straight wires carry equal currents in opposite directions . The separation between the wires is 5.0 cm. If a particle of charge 5 $μ$ C moves with a velocity 500 ms^-1into the plane of the conductors , at a point P midway between the wires , then the force on the particle will be

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zero

4 x 10^-6 N

4 x 10^-7 N

4 x 10^-5 N

answer is C.

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Detailed Solution

$\vec{F} = q (\vec{V} \times \vec{B}) \vec{V} is parallel to \vec{B} \Rightarrow F = 0$

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