Two long parallel wires P and Q are both perpendicular to the plane of the paper with distance of 5m between them. If P and Q carry current of 5A and 2.5A respectively in the same direction, then the magnetic field at a point halfway between the wires is

$\begin{array}{l}\text{ When current flow in both wire in same direction then }\\ \text{ magnetic field at half way due to P wire. }\\ {\overrightarrow{\text{B}}}_{\text{P}}=\frac{{\mu }_0{\text{I}}_1}{2\pi \frac{5}{2}}=\frac{{\mu }_0{\text{I}}_1}{\pi 5}=\frac{{\mu }_0}{\pi }({\text{ where I}}_1=2.5\text{Amp})\\ \text{ The direction of }{B}_p\text{ is downward }\otimes \\ \text{ Magnetic field at half way due to Q wire }\\ {\overrightarrow{\text{B}}}_{\text{Q}}=\frac{{\mu }_0{\text{I}}_2}{2\pi \frac{5}{2}}=\frac{{\mu }_0}{2\pi }[\text{ upward }\odot ]\\ [\text{where}{\text{I}}_{\text{2}}\text{=2}.\text{5Amp}.]\\ \text{ Net magnetic field at half way }\\ \overrightarrow{\text{B}}={\overrightarrow{\text{B}}}_{\text{P}}+{\overrightarrow{\text{B}}}_{\text{Q}}=\frac{{\mu }_0}{\pi }-\frac{{\mu }_0}{2\pi }=\frac{{\mu }_0}{2\pi }(\text{downward }\otimes )\\ \end{array}$