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Q.

Two long straight parallel wires separated by a distance, carrying equal currents exert a force F per unit length on each other. If the distance of separation is halved and the current in each doubled, the force per unit length between them will be

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a

$\frac{F}{4}$

b

$\frac{F}{8}$

c

8F

d

4F

answer is B.

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Detailed Solution

$F = \frac{μ_{0} i_{1} i_{2} l}{2 πr}; Fα \frac{i_{1} i_{2}}{r}; \frac{F}{F} = {(\frac{i}{2 i})}^{2} \times (\frac{r}{2 r})$
F' = 8F

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