Two long, straight wires carry equal currents in opposite directions as shown in figure. The separation between the wires is 5.0 cm. The magnitude of the magnetic field at a point P midway between the wires is _________ µT.(Given: $μ_{0} = 4 π \times 10^{- 7} Tm A^{- 1}$ )

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180

160

answer is A.

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Detailed Solution

$\begin{aligned} B = B_{1} + B_{2} \\ B = \frac{μ_{0} I}{2 π r} + \frac{μ_{0 I}}{2 π r} \\ B = 2 \frac{μ_{0} I}{2 π r} \\ B = 16 \times 10^{- 5} T = 160 μ T \end{aligned}$

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