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Two magnets of moments M₁and M₂ are rigidly fixed together at their center's so that their axes are inclined to each other. This system is suspended in a magnetic field of induction ‘B’ so that M₁ makes an angles $θ$ ₁ and M₂ makes an angles $θ$ ₂ with the field direction and unlike poles on either side of the field direction. The resultant torque on the rigid system is

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$B (M_{1} \sin θ_{1} + M_{2} \sin θ_{2})$

$B (M_{1} \cos θ_{2} + M_{2} \cos θ_{1})$

$B (M_{1} \cos θ_{1} + M_{2} \cos θ_{2})$

$B (M_{1} \sin θ_{2} + M_{2} \sin θ_{1})$

answer is A.

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Detailed Solution

Net torque

$τ = M_{1} Bsin θ_{1} + M_{2} Bsin (180 - θ_{2})$

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