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Q.

Two masses 5 kg and 3 kg are suspended from the ends of an unstretchable light string passing over a frictionless pulley. When the masses are released, the thrust (in N) on the pulley is (g = 10ms^–2)

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answer is 75.

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Detailed Solution

The tension in the string is given by $T = \frac{2 m_{1} m_{2}}{m_{1} + m_{2}} g$

On putting the values we get T=37.5N.

The thrust on the pulley=2T=75N

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Two masses 5 kg and 3 kg are suspended from the ends of an unstretchable light string passing over a frictionless pulley. When the masses are released, the thrust (in N) on the pulley is (g = 10ms–2)