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Two masses $50 kg$ and $100 kg$ are separated by a distance of $10 m .$ What is the gravitational force of attraction between them? ( $G = 6.67 \times 10^{- 11} N m^{2} / k g^{2})$

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3.335 \times 10^{- 9} N

33.35 \times 10^{- 9} N

3.335 \times 10^{- 10} N

3.335 \times 10^{- 11} N

answer is A.

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Detailed Solution

The gravitational force of attraction between the objects is

F = 3.335 \times 10^{- 9} N

.
Given,
The mass of first body

, m_{1} = 50 kg

and the mass of second body,

m_{2} = 100 kg

Distance between the two given masses is,

r = 10 m .

then according to Universal law of gravitation, force of attraction between two bodies is given as

F = \frac{G m_{1} m_{2}}{r^{2}}

Where

G

is the gravitational constant and

G = 6.67 \times 10^{- 11} N m^{2} / k g^{2}

F = \frac{6.67 \times 10^{- 11} \times 50 \times 100}{10^{2}}

= 33.35 \times 10^{- 10} N

= 3.335 \times 10^{- 9} N

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