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Two masses 8 kg and 4 kg are suspended together by a massless spring of spring constant $1000 {Nm}^{- 1}$ . When the masses are in equilibrium 8 kg is removed without disturbing the system. The amplitude of oscillation is

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0.5 m

0.08 m

0.4 m

0.04 m

answer is B.

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Detailed Solution

$x_{12} = \frac{12 \times 10}{1000} = 0.12 m$ $(∵ x = \frac{mg}{k})$

$x_{4} = \frac{4 \times 10}{1000} = 0.04 m$

$∴ A = x_{12} - x_{4} = 0.08 m$

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