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Q.

Two masses m and m2 are connected at the two ends of a massless rigid rod of length l. The rod is suspended by a thin wire of torsional constant k at the centre of mass of the rod-mass system (see figure). Because of torsional constant k, the restoring torque is τ= for angular displacement θ . If the rod is rotated by θ0 and released, the tension in it when it passes through its mean position will be:

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a

302l

b

022l

c

202l

d

02l

answer is D.

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Detailed Solution

solution

From the figure,

ω=kI=3k ml2 

=Angular frequency × Angular amplitude= ωθ0=  velocity at mean position

T=max2r1     =max2l3

=2θ02l3

=m3kml2θ02l3=kθ02l

Hence the correct answer is kθ02l.

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