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Q.

Two masses  m1  and m2(m1<m2) are positioned as shown in figure,  m1 being on the ground and m2  at a height above the ground. When  m2  is released, the speed at which it hits the ground will be

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a

2gh(m1+m2)(m1−m2)

b

2gh(m1−m2)(m1+m2)

c

2ghm1m2

d

2gh(m2−m1)(m1+m2)

answer is D.

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Detailed Solution

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m2gh=m1gh+12(m1+m2)v2

∴v=2gh(m2−m1)m1+m2

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