Two masses $m_{1} = 5 k g a n d m_{2} = 4.8 k g$ tied to a string are hanging over a light frictionless pulley. The acceleration of the masses when left free to move is $(g = 9.8 m s^{- 2})$

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$4.8 m s^{- 2}$

$9.8 m s^{- 2}$

$5 m s^{- 2}$

$0.2 m s^{- 2}$

answer is D.

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Detailed Solution

$m_{1} = 5 k g m_{2} = 4.8 k g, g = 9.8 m / s^{2}$ Question Image

$m_{1} g - T = m_{1} a \to (1) T - m_{2} g = m_{2} a \to (2)_________________(o n a d d i n g) g (m_{1} - m_{2}) = a (m_{1} + m_{2}) a = \frac{g (m_{1} - m_{2})}{m_{1} + m_{2}} = \frac{9.8 (5 - 4.8)}{9.8} a = 0.2 m / s^{2}$

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