Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6
Banner 7
Banner 8
Banner 9

Q.

Two masses  m1and m2 (m1<m2) are released from rest from a finite distance. They start under their mutual gravitational attraction then

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya

a

acceleration of m1 is more than that of m2

b

acceleration of m2is more than that of m1

c

centre of mass of system will remain at rest in all the references frame

d

 total energy of system remains constant

answer is A, D.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

Detailed Solution

Mutual force of attraction is same on two bodies,
but acceleration a=mF

The magnitude of force is constant but directions are opposite.

    am

As m1<m2a2<a1

Here, Potential energy is getting converted to kinetic energy.

Therefore, no energy loss.

Watch 3-min video & get full concept clarity
score_test_img

courses

No courses found

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Get Expert Academic Guidance – Connect with a Counselor Today!

best study material, now at your finger tips!

  • promsvg

    live classes

  • promsvg

    progress tracking

  • promsvg

    24x7 mentored guidance

  • promsvg

    study plan analysis

download the app

gplay
mentor

Download the App

gplay
whats app icon
personalised 1:1 online tutoring