Two masses of 10 kg and 20 kg respectively are tied together by a massless spring. A force of 200 N is applied on a 20 kg mass as shown in figure. At the instant shown, the acceleration of 10 kg mass is 12 $m / s^{2}$ , the acceleration of 20 kg mass is

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10 $m / s^{2}$

4 $m / s^{2}$

12 $m / s^{2}$

answer is C.

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Detailed Solution

Let extension in the spring is x.
For l0 kg mass: $kx = 10 a_{1} = 10 \times 10 = 120 N$
For 20 kg mass: 200 - kx = $20 a_{2}$
$\Rightarrow$ 200 - 120 = $20 a_{2}$ $\Rightarrow$ $a_{2} = 4 m / s^{2}$

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