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Two masses of 2 kg and 4 kg are connected through two strings BC and ED, which pass over a fixed frictionless pulley. The string BC is 10 cm long and has a linear mass density of 10 kg/m while the string ED is massless. If both the strings are inextensible, then (when the masses are released) the ratio of tension in the string

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At points E and C is 5/4

At points E and C is 4/5

At points D and E is 1

At points D and E is 1/2

answer is A, C.

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Detailed Solution

$a = \frac{5 g - 2 g}{7} = \frac{3 g}{7} T_{E} = 2 g + \frac{6 g}{7} = \frac{20 g}{7} T_{C} = 4 g - \frac{12 g}{7} = \frac{16 g}{7}$

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