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Two masses of $10 kg$ and $20 kg$ respectively are connected by a massless spring as shown in the figure. A force of $200 N$ acts on the $20 kg$ mass. At the instant shown the $10 kg$ mass has an acceleration $4 m / s^{2}$ rightwards. What is the acceleration of $20 kg$ mass ?

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$Z e r o$

$10 m / s^{2}$

$4 m / s^{2}$

$8 m / s^{2}$

answer is D.

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Detailed Solution

$F = 10 \times 4 = 40 N$

As the force by spring will exert force equally on both ends

$a = \frac{160}{20} = 8 m / s^{2}$

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