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Q.

Two masses m1 and m2(m1>m2)are falling from the same height when same air resistance acts on them

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a

m1has more velocity on striking the ground        

b

all the above

c

m1has more acceleration

d

m1reaches the ground early

answer is D.

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Detailed Solution

Given that two masses m1 and m2(m1>m2) are falling from the same height both are said to be experiencing same air friction f.

Question Image

We can have net force on m1

Fnet=m1g-f m1a1=m1g-f a1=g-fm1(1) Similarly net force on m2 Fnet=m2g-f m2a2=m2g-f a2=g-fm2(2) since m1>m2 from (1)&(2) we get a1>a2 and heavier bodies reaches ground earlier i.e. m1 will reach the ground earlier, , m1 will gain greater acceleration. Obviously m1  will strike the ground with greater velocity. 

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