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Two massless springs with spring constants 2k and 9k, carry 50 g and 100 g masses at their free ends. These two masses oscillate vertically such that their maximum velocities are equal. Then, the ratio of their respective amplitudes will be:

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1:2

3:2

3:1

2:3

answer is B.

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Detailed Solution

$V_{\max} = ω A$
$\Rightarrow \frac{A_{1}}{A_{2}} = \frac{ω_{2}}{ω_{1}} = \sqrt{\frac{9}{2} \times \frac{1}{2}} = \frac{3}{2}$

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