Q.

Two men of mass 60 kg and 80 kg stand on a plank of mass 20 kg as shown in the figure. Both of them can jump with a velocity of 1 m/s relative to the plank. In each event shown in column-I, find the velocity of plank after the event. 

Question Image
 Column I Column II
ARam alone jumps to the left p-1740m/s
BShyam alone jumps to the right q-12m/s
CRam jumps to left and shyam jumps to right simultaneouslyr-38m/s
DRam jumps to left and after that shyam  jumps to right s-18m/s
  t 0

see full answer

Start JEE / NEET / Foundation preparation at rupees 99/day !!

21% of IItians & 23% of AIIMS delhi doctors are from Sri Chaitanya institute !!
An Intiative by Sri Chaitanya

a

a-q b-r c-pd-s 

b

a-q; b-p; c-s; d-r

c

a-q; b-r c-p;d-s 

d

a-r ;b-q ;c-s; d-p

answer is C.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

Question Image

Pi=Pp0=60(1+v)+(80+20)vv=38 is opposite to 2 m/s 

velocity of Ram I. e 38 m/s  towards right

b 0 = 80(1+v)+(60+20)vv = - 12m/s

c 80(1+v)+60(1+v)+20 v = 0 

80 - 60 + 800 + 60 v + 20 v = 0- 20 =160 v

v = - 18m/s

(d) After jump of Ram 

Question Image

 

 

Now (80+20)38=80(1+v+20v

v = - 1740m/s

Watch 3-min video & get full concept clarity
score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon