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Two metal spheres having diameters in the ratio 2 : 3 are put into contact and a charge $20 μ C$ is given the system. Then they are separated so that there is no mutual force between them. The potential due to larger sphere at a distance of 6m is

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1800 V

answer is B.

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Detailed Solution

$v_{1} = v_{2} \Rightarrow q \propto r; \frac{q_{1}}{q_{2}} = \frac{2}{3} q_{2} = \frac{3}{5} \times 20 = 12 μ c v = \frac{k q_{2}}{6} = 18 \times 10^{3} v$

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