Q.

Two metal spheres, one of radius R and the other of radius 2R respectively have the same surface charge density σ. They are brought in contact and separated. What will be the new surface charge densities on them?

see full answer

Start JEE / NEET / Foundation preparation at rupees 99/day !!

21% of IItians & 23% of AIIMS delhi doctors are from Sri Chaitanya institute !!
An Intiative by Sri Chaitanya

a

σ1=56σ, σ2=52σ

b

σ1=52σ, σ2=53σ

c

σ1=53σ, σ2=56σ

d

σ1=52σ, σ2=56σ

answer is D.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

detailed_solution_thumbnail

when spheres are kept in contact, charge redistribution takes place to get same potential. 

Total combined charge = 20πR2σ

Potential of both the spheres become equal, hence Q = QI2 where Q is the charge on sphere of radius R and QI is the charge on sphere of radius 2R.

Thus charge on sphere of radius R becomes 20πR2σ3 , while charge on sphere of radius 2R becomes 40πR2σ3

Hence new charge densities will be

σ1=53σ, σ2=56σ

Watch 3-min video & get full concept clarity
score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon
Two metal spheres, one of radius R and the other of radius 2R respectively have the same surface charge density σ. They are brought in contact and separated. What will be the new surface charge densities on them?