Two metallic charged spheres whose radii are 20 cm and 10 cm respectively, have each 150 micro-coulomb positive charge. The common potential after they are connected by a conducting wire is

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$9 \times 10^{6} volts$

$13 .5 \times 10^{6} volts$

$4 .5 \times 10^{6} volts$

$1 .8 \times 10^{7} volts$

answer is A.

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Detailed Solution

Common potential $V = \frac{Total charge}{Total capacitance}$

$V = \frac{150 \times 10^{- 6} \times 2}{4 {πε}_{0} (10 \times 10^{- 2} + 20 \times 10^{- 2})} = 9 \times 10^{6} V$

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