Two moles of air, when heated through 10 K expand by an amount of 1.66 × 10–3 m3 under a constant pressure of 105 N/m2. If Cv = 20.81 J/mole K, then Cp is,

CP−CV=R⇒CP=CV+RCP=20.81+8.314=29.124J/mol k

Two moles of air, when heated through 10 K expand by an amount of 1.66 × 10–3 m3 under a constant pressure of 105 N/m2. If Cv = 20.81 J/mole K, then Cp is,

CP−CV=R⇒CP=CV+RCP=20.81+8.314=29.124J/mol k

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Two moles of air, when heated through 10 K expand by an amount of 1.66 × 10^–3 m³ under a constant pressure of 10⁵ N/m². If C_v = 20.81 J/mole K, then C_p is,

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29. 11J/mole K

19.11 J/mole K

32.11 J/mole k

19.11J/mole k

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$\begin{array}{l} C_{P} - C_{V} = R \Rightarrow C_{P} = C_{V} + R \\ C_{P} = 20 .81 + 8 .314 = 29 .124 J / mol k \end{array}$

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Two moles of air, when heated through 10 K expand by an amount of 1.66 × 10–3 m3 under a constant pressure of 105 N/m2. If Cv = 20.81 J/mole K, then Cp is,

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Two moles of air, when heated through 10 K expand by an amount of 1.66 × 10^–3 m³ under a constant pressure of 10⁵ N/m². If C_v = 20.81 J/mole K, then C_p is,