Two moles of air, when heated through 10 K expands by an amount of 1.66 × 10–3 m3 under a constant pressure of 105 N/m2. If Cv = 20.81 J/mole K, then Cp is,

Now, = (416.2+133)J = 529.2 J Also,

Two moles of air, when heated through 10 K expands by an amount of 1.66 × 10–3 m3 under a constant pressure of 105 N/m2. If Cv = 20.81 J/mole K, then Cp is,

Now, = (416.2+133)J = 529.2 J Also,

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Two moles of air, when heated through 10 K expands by an amount of 1.66 × 10^–3 m³ under a constant pressure of 10⁵ N/m². If C_v = 20.81 J/mole K, then C_p is,

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27.46J/mole K

19.11 J/mole K

32.11 J/mole k

19.11J/mole k

answer is A.

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Detailed Solution

$Delta W = P times Delta V = {10^5} times 1.33 times {10^{ - 3}}J$

$Rightarrow Delta W = 133J$

$Delta U = n{C_V}Delta T = 2 times 20.81 times 10J$

$Rightarrow Delta U = 416.2J$

Now, $Delta Q = Delta U + Delta W$

= (416.2+133)J

= 529.2 J

Also, $Delta Q = n{C_P}Delta T$

$therefore {C_P} = frac{{Delta Q}}{{nDelta T}} = frac{{549.2}}{{2 times 10}}J/mol - K$

$= 27.46J/mol - K$

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Two moles of air, when heated through 10 K expands by an amount of 1.66 × 10^–3 m³ under a constant pressure of 10⁵ N/m². If C_v = 20.81 J/mole K, then C_p is,