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Q.

Two moles of air, when heated through $10 K$ expand by an amount of $1.66 \times 10^{- 3} m^{3}$ under a constant pressure of $10^{5} / N / m^{2} .$ If $C_{v} = 20.81 J / m o l e K;$ then $C_{p}$ is in $J / m o l e K$

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a

$9.11$

b

$32.11$

c

$19.11$

d

$29.11$

answer is D.

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Detailed Solution

$d Q = d U + d W$

$n C_{p} d T = n C_{v} d T + P d v 2 C_{P} 10 = 2 (20.81) (10) + 10^{5} (1.66 \times 10^{- 3})$

$C_{p} = 29.11 J / m o l K$

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Two moles of air, when heated through 10K expand by an amount of 1.66×10−3m3 under a constant pressure of 105/N/m2. If Cv=20.81J/moleK; then Cp is in J/moleK